Answer by GKxx for Do the parentheses after the type name make a difference...
According to n4713:8.5.2.4/18:A new-expression that creates an object of type T initializes that object as follows:If the new-initializer is omitted, the object is default-initialized (11.6).Otherwise,...
View ArticleAnswer by uqb for Do the parentheses after the type name make a difference...
I wrote some sample codes below, as a supplement to the answer of Michael Burr:#include <iostream>struct A1 { int i; int j;};struct B { int k; B() : k(4) {} B(int k_) : k(k_) {}};struct A2 { int...
View ArticleAnswer by ThatsJustCheesy for Do the parentheses after the type name make a...
The rules for new are analogous to what happens when you initialize an object with automatic storage duration (although, because of vexing parse, the syntax can be slightly different).If I say:int...
View ArticleAnswer by kfsone for Do the parentheses after the type name make a difference...
new Thing(); is explicit that you want a constructor called whereas new Thing; is taken to imply you don't mind if the constructor isn't called.If used on a struct/class with a user-defined...
View ArticleAnswer by Michael Burr for Do the parentheses after the type name make a...
Let's get pedantic, because there are differences that can actually affect your code's behavior. Much of the following is taken from comments made to an Old New Thing articleSometimes the memory...
View ArticleAnswer by bayda for Do the parentheses after the type name make a difference...
In general we have default-initialization in first case and value-initialization in second case.For example:in case with int (POD type):int* test = new int - we don't have any initialization and the...
View ArticleAnswer by Evan Shaw for Do the parentheses after the type name make a...
Assuming that Test is a class with a defined constructor, there's no difference. The latter form makes it a little clearer that Test's constructor is running, but that's about it.
View ArticleAnswer by anon for Do the parentheses after the type name make a difference...
No, they are the same. But there is a difference between:Test t; // create a Test called tandTest t(); // declare a function called t which returns a TestThis is because of the basic C++ (and C) rule:...
View ArticleDo the parentheses after the type name make a difference with new?
If 'Test' is an ordinary class, is there any difference between:Test* test = new Test;andTest* test = new Test();
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